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The standard cell potential for Zn|Zn^(2...

The standard cell potential for `Zn|Zn^(2+) ||Cu^(2+)|Cu" is "1.10` V. When the cell is completely discharged, log `[Zn^(2+)]//[Cu^(2+)]` is closest to

A

`37.3`

B

`0.026`

C

`18.7`

D

`0.052`

Text Solution

Verified by Experts

The correct Answer is:
A
`0=1.1-(0.0591)/2 "log" (Zn^(+2))/(Cu^(+2))`
`-1.1=(0.0591)/2 log. (Zn^(+2))/(Cu^(+2))`
`"log" (Zn^(+2))/(Cu^(+2))=37.3`
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