An organic compound having molecular formula `C_(2)H_(6)O` undergoes oxidation with `K_(2)Cr_(2)O_(7)//H_(2)SO_(4)` to produce X which contains `40%` carbon, `6.7%` hydrogen and `53.3%` oxygen. The molecular formula of the compound X is

Options

A. `CH_(2)O`
B. `C_(2)H_(4)O_(2)`
C. `C_(2)H_(4)O`
D. `C_(2)H_(6)O_(2)`

Answer

B

Explanation

`underset(underset(underset((C_(n)H_(2n+2)O))("Alcohol"))((C_(2)H_(60))))(CH_(3)-CH_(2)-OH)overset(K_(2)Cr_(2)O_(7)//H_(2)SO_(4))to underset(underset(underset(underset(underset(H=4(6.7%))(O=32(53.3%)))(C=24(40%" carbon")))("Total wt = 60"))("Carboxylic acid"))underset(O" ")underset(||" ")(CH_(3)-C-O-H)`