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A reaction has an activation energy of 2...

A reaction has an activation energy of 209 KJ `"mol"^(-1)` . The rate increase 10-fold when the temperature is increased from `27^(@)C` to `X ""^(@)C` . The temperature X is closed to
[Gas constant, R =`8.314 J "mol"^(-1) K^(-1)`]

A

35

B

40

C

30

D

45

Text Solution

Verified by Experts

The correct Answer is:
A
`log_(10)=(209xx10^(3))/(2.303xx8.314)[(1)/(300)-(1)/(T)]`
`9.16xx10^(-5)=3.33xx10^(-3)-(1)/(T)`
`T=308.4 K`
or `35^(@)C=X`
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