A container of volume 2.24 L can withstand a maximum pressure of 2 atm K before exploding. The maximum amount of nitrogen (in g) that can be safely put in this container at this temperature is closest to

Options

A. 2.8
B. 5.6
C. 1.4
D. 4.2

Explanation

The maximum amount of nitrogen that can be sefely put in this container must, exert a oressure less then 2 atom at 298K.
i.e., maximum moles in container `n=(PV)/(RT)`
`=(2xx2.24)/(0.0821xx298)=0.18`
I.e., maximum weight of `N_(2)" in container "=0.1821xx28=5.127 gm`.
The correct answer is, (D) 4.2 grams
for sefety concem, we con't go for adding more nitrogen.