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The tendency of X in BX(3)(X=F,Cl,OMe, N...

The tendency of X in `BX_(3)(X=F,Cl,OMe, NMe)` to form a `pi` bond with boron follows the order

A

`BCl_(3) lt BF_(3) lt B(OMe)_(3) lt B (NMe_(2))_(3)`

B

` BF_(3) lt BCl_(3) lt B(OMe)_(3) lt B (NMe_(2))_(3)`

C

`BCl_(3) lt B(NMe_(2))_(3) lt B(OMe)_(3) lt BF_(3)`

D

`BCl_(3) lt BF_(3) lt B(NMe_(2))_(3) lt B(OMe)_(3)`

Text Solution

Verified by Experts

The correct Answer is:
A

Reason : Better extent of back bonding , Note-Cl can't donte 3p electron pair to boron as fluorine because of large size 3p orbital.
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