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The mean deviation for n observations x...

The mean deviation for `n` observations `x_1, x_2, ......... , x_n` from their mean ` X ` is given by (a)`sum_(i=1)^n(x_i- X )` (b) `1/nsum_(i=1)^n(x_i- X )` (c) `sum_(i=1)^n(x_i- X )^2` (c) `1/nsum_(i=1)^n(x_i- X )^2`

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Verified by Experts

As we know from the property
`=>1/nsum_(i=1)^n(x_i- overlinex )`
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