[x^(3)+3x^(2)+3x+1" To finferizan the the for the for "],[[" (1) "x+1," (ii) "x-(1)/(2)," (iii) "x," (iv) "x+pi," (v) "5+2x]]

1) x-(1)/(2)sqrt(x^(3)+3x^(2)+3x+1)

solve for x (2x-5)/(3x-1)=(2x-1)/(3x+2)

If x^(4) - 3x^(2) - 1 = 0 , then the value of (x^(6)-3x^(2)+(3)/(x^(2))-(1)/(x^(6))+1) is :

(x^(2)-x)-(1)/(2)(x-3+3x^(2))

The solution of (2x+3)/(2x - 1) = (3x-1)/(3x + 1) is

x^(2)+(1)/(x^(2))-2-3x+(3)/(x)

(i) (2x+3) (3x-5) (ii) x(1+x)^(3) (iii) (sqrtx + 1/x) (x -1/sqrtx) (iv) (x-1/x)^(2) (v) (x^(2) + 1/x^(2))^(3) (vi) (2x^(2) +5x-1) (x-3)