`C_(3)H_(6)Cl_(2)` on reaction with `NaOH` forms `C_(3)H_(6)O`,which gives yellow precipitate on heating with `NaOH` and `I_(2)` .Thus`C_(3)H_(6)Cl_(2)` is:

An organic compound A (C_(7)H_(6)Cl_(2)) on treatment with NaOH solution gives another compound B (C_(7)H_(6)O) . B on oxidation gives and acid C (C_(7)H_(6)O_(2)) which on treatment with a mixture of conc. HNO_(3)" and "H_(2)SO_(4) gives a compound D (C_(7)H_(5)NO_(4)) . B on treatment with conc. NaOH gives a compound E (C_(7)H_(8)O)" and "C_(6)H_(5)COONa . Deduce the structures of [A], [B], [C], [D] and [E].

A and B are functional isomers of compound C_(3)H_(6)O . On heating with NaOH and I_(2) isomer A froms yellow percipitate of iodoform whereas isomer B does not form any precipitate. Write the formulae of A and B.

What is the general formula of alkenes? Identify the alkenes from the following? C_(2)H_(6), C_(2)H_(4), C_(3)H_(4), C_(2)H_(2), C_(3)H_(6) Which of the following can give addition reactions? C_(2)H_(6), C_(3)H_(8), C_(3)H_(6), C_(2)H_(6), C_(2)H_(2), CH_(4) Give reason for your choice.