A body moves along `x`-axis with velocity `V_(x)` at position `x`. If the plot `v_(x)-x` is an ellipse with major axis `2A` and minor axis `2V_(0)` the maximum acceleration has a modulus

A particle moves along the X-axis with velocity v = (dx)/(dt)=f(x) then the acceleration of the particle is

If v is the velocity of a body moving along x-axis, then acceleration of body is

If v is the velocity of a body moving along x-axis, then acceleration of body is

A particle of unit mass is moving along x-axis. The velocity of particle varies with position x as v(x). =alphax^-beta (where alpha and beta are positive constants and x>0 ). The acceleration of the particle as a function of x is given as

A particle of unit mass is moving along x-axis. The velocity of particle varies with position x as v(x). =alphax^-beta (where alpha and beta are positive constants and x>0 ). The acceleration of the particle as a function of x is given as

The equation of the ellipse with it's major axis is x-axis, minor axis is y-axis, eccentricity is 2/3 and the length of major axis is 12 is

A body starts from origin and moves along x - axis so that its position at any instant is x=4t^(2)-12t where t is in second and v in m/s. What is the acceleration of particle?

body moves along x-axis with velocity v = 5 sin(2t)m/s starting from x_i =-2.5 m Total distance traveled by the body with its acceleration directed along +ve x-axis in 3pi//2 sec will be :

A particle moves along x-axis with acceleration a=6(t-1) where t is in second. If the particle is initially at the origin and it moves along positive x-axis with v_(0)=2m//s , find the nature of motion of the particle.