f(x)={[kx+1,x<=pi],[cos x,x>pi]

If the p.d.f. of a c.r.v. X is f(x)={(kx^2 (1-x^3)","0lexle1,),(0",",elsewhere):} then :k…

The function is defined by f(x) = {(kx+1,if, x lepi),(cos x,if, x gt pi):} at x = pi .

If 'f(x)= {[Kx+1,xle5],[3x-5,x>5]:}' is continuous at x=5 then value of k is :

Find the value of k for which the function f(x) f(x)={(kx+1,xlex),(cosx,xgtpi):} is continuous at x = pi

(v) If f(x)={ kx^(2) x>=1 4 x<1 is continuous at x=1 then the value of k is:

If f(x)= kx-sin x is monotonically increasing then

f(x) = { (kx+1, x le pi),( cos x, x >pi):} If f(x) is continous at x = pi then find k.

Find the values of k so that the function f is continuous at the indicated point : f(x)={(kx+1,,,, if x lepi),(cosx,,,, if x>pi):} at x=pi

If f(x)={(kx-1" , "xle5),(3x-5" , "xgt5):} is continuous at x=5 then value of k is: