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[" If "sin theta+cos theta=1" then "sin2...

[" If "sin theta+cos theta=1" then "sin2 theta=],[(1)0]quad [" (2) "1],[[" (1) "0]]

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If sin theta+cos theta=1, then the value of sin2 theta is equal to

If sin theta+cos theta=1 then the value of sin 2 theta is equal to

sin theta+cos theta=1 Find (sin theta-cos theta)^(2)

(sin theta + cos theta)^2 = 1 + 2 sin theta cos theta

((1 + sin theta-cos theta) / (1 + sin theta + cos theta)) ^ (2) =

(1+sin 2theta+cos 2theta)/(1+sin2 theta-cos 2 theta) =

(1+sin 2theta+cos 2theta)/(1+sin2 theta-cos 2 theta) =

((1+ sin theta - cos theta )/( 1+ sin theta + cos theta ))^(2)=

int(sin theta+cos theta)/(sqrt(1+sin2 theta))d theta

(1+sin2theta+cos2theta)/(1+sin2theta-cos2theta)=?