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[sin(90-theta)=cos theta],[-3(90-theta)=...

[sin(90-theta)=cos theta],[-3(90-theta)=sin theta]

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Simplify: (sin(90-theta)costheta)/(cos(90-theta)sintheta)+1=

sin(90^(@)-theta)costheta+cos(90^(@)-theta)sintheta= ………… .

Prove that :(sin theta cos(90^(0)-theta)cos theta)/(sin(90^(0)-theta))+(cos theta sin(90^(0)-theta)sin theta)/(cos(90^(@)-theta))=1csc^(2)(90^(@)-theta)-tan^(2)theta=cos^(2)(90^(@)-theta)+cos^(2)theta

Evaluate (sin (90 - theta). cos (90 - theta))/(sin theta cos theta)

Which of the following statement is true? (A) sin theta=cos (90-theta) (B) cos theta=tan (90-theta) (C) sin theta=tan(90-theta) (D) tan theta=tan (90-theta)

Without using trigonometrical tables; prove (sin theta)/(sin(90-theta))+(cos theta)/(cos(90^(@)-theta))=sec theta*cosec theta

Prove the following identities: (i) costhetasin(90^o-theta)+sinthetacos(90^o-theta)=1 (ii) (sin(90^o-theta))sintheta/(tantheta)-1=-sin^2theta (iii) (sin(90^o-theta)cos(90^o-theta))/(tantheta)=1-sin^2theta

Prove that : (sinthetacos(90^0-theta)costheta)/(sin(90^0-theta))+(costhetasin(90^0-theta)sintheta)/(cos(90^0-theta))=1

Evaluate cos thetasin theta + cos thetacos (90 - theta) + {(sin theta - sin (90 - theta)}^2 .

Prove the following identities: cos theta sin(90o-theta)+sin theta cos(90o-theta)=1sin(sin(90o-theta))/(tan theta)-1=-sin^(2)theta( iii) (sin(90o-theta)cos(90o-theta))/(tan theta)=1-sin^(2)theta