[" A girl is twice as old as her sister.Four years hence,the product of "],[" their ages (in years) will be "160." Find their present ages."" [CBSE "2010" ."]

A girl is twice as old as her sister. Five years hence, the product of their ages (in years) will be 375. Find their present ages.

If 2 is added to numerator and denoinator to a fraction, it becomes 9/10 . If 3 is subtracted from numerator and denominator , the fraction becomes 4/5 . Find the fraction. OR A girl is twice as old as her sister. Four years, hence the product of their ages ( in years) will be 160. Find their present ages.

Age of Vineetha is twice her sisters age. After 4 years the product of their ages will be '160 .' Find the present ages of both.

A woman is six times as old as her son.Two years ago,the product of their ages was 84. Find their present ages.

Product of Pragati's age 2 years ago and 3 years hence is 84. Find her present age.

Product of Pragati's age 2 years ago and 3 years hence is 84. Find her present age.

Product of Pragati's age 2 years ago and 3 years hence is 84. Find her present age.