96abc(3a-12)(5b-30)-:144(a-4)(b-6)

Work out the following divisions. 96abc(3a-12)(5b-30) div 144(a-4)(b-6)

5/4-7/6-(-2)/3=\ 3/4 (b) -3/4 (-7)/(12) (d) 7/(12)

If a/b=4/3, then the value of (6a+4b)/(6a-5b) is -1 (b) 3 (c) 4 (d) 5

If a/b=4/3, then the value of (6a+4b)/(6a-5b) is (a) -1 (b) 3 (c) 4 (d) 5

If A=[{:(2,-1,3),(4,5,-6):}] and B=[{:(1,2),(3,4),(5,-6):}] then

If A=[(3,0),(-4,-1)]B=[(3,5,-7),(0,-1,8)]C=[(6),(-1),(0)] then ABC=

sum_(n=3)^(oo)(1)/(n^(5)-5n^(3)+4n)(A)(1)/(120) (B) (1)/(96)(C)(1)/(24) (D) (1)/(144)

The value of sum_(n=3)^(oo)(1)/(n^(5) - 5n^(3) +4 n) is equal to - (a) (1)/(120) (b) (1 )/(96) (c) (1)/(24) (d) (1)/(144)

If A=[[1,2,3]], B=[(-5,4,0),(0,2,-1),(1,-3,2)] then (A) AB=[(-2),(-1),(4)] (B) AB=[-2,-1,4] (C) AB=[4,-1,2] (D) AB=[(-5,4,0),(0,4,-2),(3,-9,6)]