" (iii) "(8^(1/3)times16^(1/3))/(32^(-1/3))

Simplify: (8^(1/3)xx16^(1/3))/(32^(-1/3))

simplify (i) (1^(3)+2^(3)+3^(3))^(1/2) (ii) (3/5)^(4)(8/5)^(-12)(32/5)^(6) ,(iii) (1/27)^(-2/3) (vi) [((625)^(-1/2)))^(-1/4)]^(2) ,(v) (9^(1/3)xx27^(-1/2))/(3^(1/6)xx3^(-2/3)) (vi) 64^(-1/3)[64^(1/3)-64^(2/3)] (8^(1/3)xx16^(1/3))/(32^(-1/3)

simplify (i) (1^(3)+2^(3)+3^(3))^(1/2) (ii) (3/5)^(4)(8/5)^(-12)(32/5)^(6) ,(iii) (1/27)^(-2/3) (vi) [((625)^(-1/2)))^(-1/4)]^(2) ,(v) (9^(1/3)xx27^(-1/2))/(3^(1/6)xx3^(-2/3)) (vi) 64^(-1/3)[64^(1/3)-64^(2/3)] (8^(1/3)xx16^(1/3))/(32^(-1/3)

((1)/(4))^(3)times((16)/(5))^(3)

1.Simplify : (3)^(-5)times(1/3)^(2)times(1/3)^(-8)

((8)^(1/3)+sqrt(16))=?

{(1/3)^2}^4 is equal to (a) (1/3)^6 (b) (1/3)^8 (c) (1/3)^(24) (d) (1/3)^(16)

{(1/3)^2}^4 is equal to (1/3)^6 (b) (1/3)^8 (c) (1/3)^(24) (d) (1/3)^(16)

the value of [(0.16)^(log_(0.25)((1)/(3)+(1)/(32)+(1)/(3^(3))+...............+oo)]^((1)/(2))) is

16/9 xx (-1(1)/2)^(3)=