" vi) "a^(3)b" and "ab^(3)

Find the geometric means of the following pairs of number: a^(3)b and ab^(3).

Divide the given polynomial by the given monomial (11a^(3)b - 5ab^(3)) div ab

Simplify the following: (6) (i) (a^(3)b^(2)c-ab^(3)c)-(3abc^(3)-a^(3)b^(2)c)-(4ab^(3)c+2abc^(3))

If a + b + 1 = 0, then the value of (a^(3) + b^(3) +1 -3ab) is

What must be sutracted from a ^(3) - 3a ^(2) b + 3 ab ^(2) - b ^(3) get a ^(3) - b ^(3) ?

If a + b + c = 0 , show that a^(3) + b^(3) + c^(3) = 3abc The following are the steps involved in showing the above result. Arrange them in sequential order (A) a^(3) + b^(3) + 3ab (-c) = -c^(3) (B) (a + b)^(3) = (-c)^(3) (C) a + b + c = 0 rArr a + b = -c (D) a^(3) + b^(3) + 3ab (a +b) = -c^(3) (E) a^(3) + b^(3) + c^(2) = 3abc