10^(2y)=25^(x)-10^(-y)=

The equation of a circle with radius 5 and touching both the coordinate axes is x^(2)+y^(2)+-10x+-10y+5=0x^(2)+y^(2)+-10x+-10y=0x^(2)+y^(2)+-10x+-10y+25=0x^(2)+y^(2)+-10x+-10y+51=0

The foci of the ellipse 9x^(2)+ 5(y^(2)-10y +25)=45 are

Form the differential equation by eliminating A,B from y=e^(5x) (Ax+B) is (A) (d^(2)y)/dx^(2) +10(dy /dx) +25y=0 (B) (d^(2)y) /dx^(2) -10(dy /dx)+25y=0 (C) (d^(2)y) /dx^(2) +10(dy /dx) -25y=0 (D) (d^(2)y) /dx^(2) -10(dy /dx) -25y=0

If (2.5)^(x)=(0.025)^(y)=10^(3) , then the value of (1)/(x)-(1)/(y) is

The limiting points of the coaxial system containing the two circles x^(2)+y^(2)+2x-2y+2=0 and 25(x^(2)+y^(2))-10x-80y+65=0 are

The limiting points of the coaxial system containing the two circles x^(2)+y^(2)+2x-2y+2=0 and 25(x^(2)+y^(2))-10x-80y+65=0 are

If log_(10)(x^(3)+y^(3))-log_(10)(x^(2)+y^(2)-xy) =0,y>=0 is

(x/10+y)(x/10-y)=?

The equation to the locus of a point P for which the distance from P to (0,5) is double the distance from P to y -axis is 1) 3x^(2)+y^(2)+10y-25=0 2) 3x^(2)-y^(2)+10y+25=0 3) 3x^(2)-y^(2)+10y-25=0 4) 3x^(2)+y^(2)-10y-25=0