[" The intitial velocity of the particle is "10m/sec" and its retardation "],[" is "2m/sec^(2)" .The distance moved by the particle in "5th" second "],[" of its motion is "]

The initial velocity of the particle is 10m//sec and its retardation is 2m//sec^(2) . The distance moved by the particle in 5th second of its motion is

The initial velocity of a particle moving along straight line is 20 m/s and its retardation Is 2 m/s_2. The distance moved by the particle in the fifth sec. of its motion is :

A particle is moving along straight line with initial velocity +7m//sec and uniform acceleration -2m//sec^(2) . The distance travlled by the particle in 4th second of its motion is:

A particle has an initial velocity of 9m//s due east and a constant acceleration of 2m//s^(2) due west. The distance coverd by the particle in the fifth second of its motion is :

A particle is moving along a straight line.The initial velocity is 10m/s and it is , moving with constant retardation of 2m/s^(2) .. The distance travelled by the particle until it comes to rest is

A particle is moving under a constant acceleration of 3m//s^(2) . The initial velocity of the particle is 10m/s. calculate the distance travelled by the particle is 5s and also in th 5th second of its motion.

If body having initial velocity zero is moving with uniform acceleration 10m//sec^(2) the distance travelled by it in third second will be

A particle starts moving with acceleration 2 m//s^(2) . Distance travelled by it in 5^(th) half second is

A particle starts moving with acceleration 2 m//s^(2) . Distance travelled by it in 5^(th) half second is