" (ii) "(4)^(2x-1)-(16)^(x-1)=384

If (4)^(2x- 1) - (16)^(x-1) = 384. find the value of x .

underset(xrarr16)"lim"(x^(1/4)-(16)^(1/4))/(x-16)= ?

Simplify: (i) (x-y)(x+y)x^2+y^2)\ (x^4+y^4) (ii) (2x-1)\ (2x+1)(4x^2+1)(16 x^4+1) (iii) (7m-8n)^2+(7m+8n)^2

(2^(x-1)*4^(x+1))/(8^(x-1))=16

The equation of the ellipse having a vertex at (6,1) a focus at (4,1) and the eccentricity (3)/(5) is 1) ((x-1)^(2))/(16)+((y-1)^(2))/(25)=1 (2) ((x-1)^(2))/(25)+((y-1)^(2))/(16)=1 3) ((x+1)^(2))/(25)+((y+1)^(2))/(16)=1 (4) ((x+1)^(2))/(16)+((y+1)^(2))/(25)=1

16. "4^(x)-3^(x-(1)/(2))=3^(x+(1)/(2))-2^(2x-1).

Evaluate the following integrals : (i) int(2(x+16)^((1)/(2))+(x+16)^((3)/(4)))/(x(x+16)^((5)/(4)))dx (ii) int(1+x^((1)/(2))-x^((2)/(3)))/(1+x^((1)/(3)))dx

Evaluate the following integrals : (i) int(2(x+16)^((1)/(2))+(x+16)^((3)/(4)))/(x(x+16)^((5)/(4)))dx (ii) int(1+x^((1)/(2))-x^((2)/(3)))/(1+x^((1)/(3)))dx

Solve : (x-4)(x-7)(x-2)(x+1)=16