If `I_n=int_0^(pi/4) sec^n dx` then `I_(10) -8/9I_8=`

If I_(n) = int_0^(pi/2) sin^(n)x dx then I_(n)/(I_(n-2)) =

If I_(n) = int_(0)^(pi//4) tan^(n) x dx then (1)/(I_(3)+I_(5))=

If I_(n)=int_(0)^(pi//4) tan^(n)x dx , then (1)/(I_(2)+I_(4)),(1)/(I_(3)+I_(5)),(1)/(I_(4)+I_(6)),... from\

If I_(n) = int_(0)^(pi//4) Tan^(n) x dx then I_(2)+I_(4), I_(3)+I_(5), I_(4)+I_(6)..... are in

If I_(n)=int_(0)^(pi//4) tan^(n)x dx , then (1)/(I_(2)+I_(4)),(1)/(I_(3)+I_(5)),(1)/(I_(4)+I_(6)),... from\

If I_(n)=int_(0)^(pi//4)tan^(n)x dx, then 7(I_(6)+I_(8))=

If I_(10) = int_0^(pi/2) x^(10) sin x dx then I_(10) + 90I_(8) =

If I_(n) = int_0^(pi/4) tan^(n)x dx , then n(I_(n-1)+I_(n+1)) =

I_n= int_0^(pi/4) tan^(n)xdx then I_3+I_5 is