" (cosec "A-sin A)(sec A-cos A)=(1)/(tan A+cot A)

Prove the following identity,where the angles involved are acute angles for which the expressions are defined.( ix) (csc A-sin A)(sec A-cos A)=(1)/(tan A+cot A)[ Hint : Simplify L.HS and RHS separately]

Prove the following trigonometric identities: (cosec A - sin A)(sec A - cos A)(tan A + cot A) = 1

Prove the following identities : (cosec A - sin A) (sec A - cos A) (tan A + cot A) = 1

What is the value of (cosec A - sin A) (sec A - cos A) (tan A + cot A) ?

(cosec x-sin x)(sec x-cos x)(tan x+cot x)

(cosec x-sin x)(sec x-cos x)(tan x+cot x)=1

(cosec A - sin A)^2 + (sec A - cos A)^2 - (cot A - tan A)^2 is equal to

What is (cosec x - sin x ) (sec x- cos x) (tan x + cot x) equal to ?

Prove that (i) (tan A+ sin A)/(tan A- sin A)= (sec A+1)/(sec A-1) (ii) (cot A- cos A)/(cot A+ cos A)= ("cosec" A-1)/("cosec" A+1)

Prove that : (tan A + cot A) (cosec A - sin A) (sec A - cos A) = 1