" The D.E whose solution is "xy=ae^(x)+be^(-x)" is "

The order of the differential equation whose solution is ae^(x) + be^(2x) + ce^(3x) + d = 0 is

The differential equation whose solution is y = Ae^(3x) + Be^(-3x) , where A, B are arbitrary constant, is

D.E whose solution is y=e^(3x)(c_(1)cos x+c_(2)sin x)

The differential equation by eliminating the arbitrary constant from the equation xy=ae^(x)+be^(-x)+x^(2) is xy_(2)+ky_(1)-xy=k then k=

Form the differential equation by eliminating the arbitrary constant from the equation xy = ae^(x) + be^(-x) + x^(2)

Find the differential equation whose solution represents the family y=ae^(x)+be^(x) .