x^(3)-23x^(2)+142x-120

Find the value of k for which (x-1) is a factor of polynomial x^(3)+kx^(2)+142x-120

Factorise x^3-23 x^2+142 x-120 .

Divide the following polynomial p(x) by polynomial s(x) p(x)=2x^(3)-13x^(2)+23x-12,s(x)=2x-3

which one of the following sets has elements as odd positive integers (a) S={x in R|x^(3)-8x^(2)+19x-12=0} b) S={x in R|x^(3)-9x^(2)+23x-15=0} c) S={x in R|x^(3)-7x^(2)+14x-8=0} d) S={x in R|x^(3)-12x^(2)+44x-48=0}

If x=(1)/(2)(5-3i), then find the value of x^(4)-x^(3)-12x^(2)+23x+12

Find the value of x.x^(3)-9x^(2)+23x-15=0

Factorise x ^(3) - 23 x ^(2) + 142 x -120

Factorise x ^(3) - 23 x ^(2) + 142 x -120

Factorise x ^(3) - 23 x ^(2) + 142 x -120