f(x)=cos2x" Annral "[0,pi]

f(x)=cos2x, interval [-(pi)/(4),(pi)/(4)]

Statement 1: Let f(x)=sin(cos x) in [0,(pi)/(2)]* Then f(x) is decreasing in [0,(pi)/(2)] Statement 2:cos x is a decreasing function AA x in[0,(pi)/(2)]

Find the maximum and minimum value of f(x)=sin x+(1)/(2)cos2x in [0,(pi)/(2)]

Find the maximum and minimum values of f(x)=sin x+(1)/(2)cos2x in [0,pi/2]

The maximum value of f(x)=sin x+cos2x when in[0,2 pi] is

f(x)=|cos2x|; then f'((pi)/(4)+theta) is equal to

Evaluate : int_(0)^(3) f(x) dx , where f(x)={(cos2x",",0 le x le (pi)/(2)),(3",",(pi)/(2) le x le 3):}

If f f(x)=cos[pi^2]x+cos[-pi^2]x where [x] stands for the greatest integer functions, then evaluate f(pi/2),f(pi),f(-pi), andf(pi/4) .

If f(x)=cos[pi^2]x+cos[-pi^2]x then the value of f(pi/4)+f(pi/2) is

If f(x)=cos[pi^2]x +cos[-pi^2]x , where [x] stands for the greatest integer function, then (a) f(pi/2)=-1 (b) f(pi)=1 (c) f(-pi)=0 (d) f(pi/4)=1