" 14.The least value of the function "f(x)=x^(3)-18x^(2)+96x" in the interval "[0,9]" is "(a)126" (b) "135" (c) "160" (d) "0

Find the least value of the function f(x)=x^3-18 x^2+96 x in the interval [0,9] is ?

The least value of the function f(x)=x^(3)-18x^(2)+96x in the interval [0,9] is 126(b)135(c)160(d)0

The least value of the function f(x)=x^3-18 x^2+96 x in the interval [0,9] is 126 (b) 135 (c) 160 (d) 0

The least value of the function f(x)=x^3-18 x^2+96 x in the interval [0,9] is 126 (b) 135 (c) 160 (d) 0

The Minimum value of the function f(x)=x^(3)-18x^(2)+96x in [0,9]

The least value of the function f(x) = 2 cos x + x in the closed interval [0,pi/2] is

The smallest value of the polynomial x^(3)-18x^(2)+96x is [0,9] is

The least value of the function f(x) = 2 cos x + x in the closed interval [0, (pi)/(2)] is:

The maximum value of the function f(x)=((1+x)^(0. 6))/(1+x^(0. 6)) in the interval [0,1] is 2^(0. 4) (b) 2^(-0. 4) 1 (d) 2^(0. 6)

The maximum value of the function f(x)=((1+x)^(0. 6))/(1+x^(0. 6)) in the interval [0,1] is 2^(0. 4) (b) 2^(-0. 4) 1 (d) 2^(0. 6)