[2x^(2)y^(-5)],[25*4x+6y=3xy],[8x+9y=5xyquad (x!=0,y!=0)]

4 x + 6y = 3 xy , 8x + 9 y = 5xy ( x ne 0 , y ne 0 )

6x+3y=6xy; 2x+4y=5xy

If 4x + 6y = 3 xy and 8x + 9y = 5xy then

x + y = 5 xy , 3x + 2y = 13 xy ( x ne 0, y ne 0 )

If the lines 2x^(2)-5xy+3y^(2)+8x-9y+6=0 and kx-y-5=0 are concurrent, then k=

Solution of D.E (dy)/(dx)=(2x+5y)/(2y-5x+3) is,if (y(0)=0) (1) x^(2)-y^(2)+5xy-3y=0 (2) x^(2)+y^(2)+5xy-3y=0 (3) x^(2)-y^(2)+5xy+3y=0 (4) x^(2)-y^(2)-5xy-3y=0

Add : 4x^(2)y, - 3xy^(2), -5xy^(2), 5x^(2)y

Add: 4x^2y, – 3xy^2, –5xy^2, 5x^2y

Add: 4x^2y,-3xy^2,5xy^2,5x^2y