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" 8."(1+x^(2))dy+2xydx=cot xdx(x!=0)...

" 8."(1+x^(2))dy+2xydx=cot xdx(x!=0)

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Find the general solution of the differential equations: quad (1+x^(2))dy+2xydx=cot xdx(x!=0)

Solve the following differential equation: (1+x^(2))dy+2xydx=cot xdx;x!=0

Solve (1 + x^(2))dy + 2xy dx = cot x dx (x ne 0)

(1 + x^(2))dy + 2xy dx = cot x dx (x ne 0)

( 1+x ^(2)) dy + 2xy dx =cot x

For each of the differential equations given in (1+x^(2))dy+2xydx=tanxdx(xne0)