`x^2+y^2-4x-6y+3=0` find `(dy)/(dx)` at `(1, 6)`

If y=6 x^(5)-4x^(4)+2x^(2)+3x+2 , then find (dy)/(dx) at x=-1.

If y=6 x^(5)-4x^(4)+2x^(2)+3x+2 , then find (dy)/(dx) at x=-1.

Find dy/dx if y(1-x^2)=6

Find (dy)/(dx) if x^6+y^6+6x^2y^2=16

If x^2+y^2-4x-6y+13=0 , then find the value of (x+y):(y-x).

Find the equation of the normal at the specified point to each of the following curves x^(2)+y^(2)-4x-6y+3=0 "at" (1,6)

y=x^(3)-4x^(2)+5 . Find (dy)/(dx) , (d^(2) y)/(dx^(2)) and (d^(3)y)/(dx^(3)) .

Find (dy)/(dx) for y =(x^2 + 4x + 6)^5

Find dy/dx if x= y^2-6y+11