An eight digit number divisible by `9` is to be formed using digits from `0` to `9` without repeating the digits. The number of ways in which this can be done is: (A) 40(7!) (B) 36(7!) (C) 18(7!) (D) 72(7!)

A five digit number divisible by 3 is to be formed using the digits 0,1,3,5,7,9 without repetitions. The total number of ways this can be done is

How many four-digit numbers divisible by 10 can be formed using 1, 5, 0, 6, 7 without repetition of digits ?

5 digit number divisible by 9 are to be formed by using the digits 0,1,2,3,4,7,8 without repetition.The total number of such 5 digited numbers formed is:

A seven-digit number without repetition and divisible by 9 is to be formed by using seven digits out of 1, 2, 3, 4, 5, 6, 7, 8, 9. The number of ways in which this can be done is (a) 9! (b) 2(7!) (c) 4(7!) (d) non of these

A seven-digit number without repetition and divisible by 9 is to be formed by using seven digits out of 1, 2, 3, 4 5, 6, 7, 8, 9. The number of ways in which this can be done is (a) 9! (b) 2(7!) (c) 4(7!) (d) non of these

A seven-digit number without repetition and divisible by 9 is to be formed by using seven digits out of 1, 2, 3, 4, 5, 6, 7, 8, 9. The number of ways in which this can be done is (a) 9! (b) 2(7!) (c) 4(7!) (d) non of these

5 digit number divisible by 9 are to be formed by using the digits 0, 1, 2, 3, 4, 7, 8 without repetition. The total number of such 5 digited numbers formed is

A seven-digit number without repetition and divisible by 9 is to be formed by using seven digits out of 1,2,3,45,6,7,8,9. The number of ways in which this can be done is (a) 9! (b) 2(7!) (c) 4(7!) (d) non of these