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sum of 1+3+5+.......+(2m-1)...

sum of 1+3+5+.......+(2m-1)

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sum_(k=1)^(5) (1^3 + 2^3 + ..... + k^3)/(1+3+5+..... + (2k-1) )=

Subtract the sum of 3(5)/(9) and 3(1)/(3) from the sum of 5(5)/(6) and 4(1)/(9)

Three particles of masses m , m and 4kg are kept at a verticals of triangle ABC . Coordinates of A , B and C are (1,2) , (3,2) and (-2,-2) respectively such that the centre of mass lies at origin. Find the value of mass m . Hint. x_(cm)=(sum_(i-1)^(3)m_(i)x_(i))/(sum_(i=1)^(3)m_(i)) , y_(cm)=(sum_(i=1)^(3)m_(i)y_(i))/(sum_(i=1)^(3)m_(i))

Three particles of masses m , m and 4kg are kept at a verticals of triangle ABC . Coordinates of A , B and C are (1,2) , (3,2) and (-2,-2) respectively such that the centre of mass lies at origin. Find the value of mass m . Hint. x_(cm)=(sum_(i-1)^(3)m_(i)x_(i))/(sum_(i=1)^(3)m_(i)) , y_(cm)=(sum_(i=1)^(3)m_(i)y_(i))/(sum_(i=1)^(3)m_(i))

Three particles of masses m , m and 4kg are kept at a verticals of triangle ABC . Coordinates of A , B and C are (1,2) , (3,2) and (-2,-2) respectively such that the centre of mass lies at origin. Find the value of mass m . Hint. x_(cm)=(sum_(i-1)^(3)m_(i)x_(i))/(sum_(i=1)^(3)m_(i)) , y_(cm)=(sum_(i=1)^(3)m_(i)y_(i))/(sum_(i=1)^(3)m_(i))

The sum of the series 1/1.2-1/2.3+1/3.4-1/4.5+ ... is

The sum of series 2[ 7^(-1)+3^(-1).7^(-3)+5^(-1).7^(-5)+...] is

The sum of series 2[ 7^(-1)+3^(-1).7^(-3)+5^(-1).7^(-5)+...] is

sum_(k=1)^(5) (1^(3)+2^(3)+.. ..+k^(3))/(1+3+5+.. ..+(2 k-1))=