Cross-multiplication method for solving equations of the form `(ax+b)/(cx+d) = m/n`

int(ax+b)/(cx+d)dx

By cross multiplication method,solve the pair of equation: ax+by+a=0, bx+ay+b=0

Equations of the form ax+by=c and bx+ay=d where a!=b

If the integrand is a rational function of x and fractional power of a linear fractional of the form (ax+b)/(cx+d) , then rationalization of the integral is affected by the substitution (ax+b)/(cx+d)=t^(m) , where m is L.C.M. of fractional powers of (ax+b)/(cx+d) . If int(dx)/((x-1)^(3//4)(x+2)^(5//4))=A((x-1)/(x+2))^(1//4)+C then

If the integrand is a rational function of x and fractional power of a linear fractional of the form (ax+b)/(cx+d) , then rationalization of the integral is affected by the substitution (ax+b)/(cx+d)=t^(m) , where m is L.C.M. of fractional powers of (ax+b)/(cx+d) . If int(dx)/((x-1)sqrt(1-x^(2)))=ksqrt((x+1)/(1-x))+C then

If the integrand is a rational function of x and fractional power of a linear fractional of the form (ax+b)/(cx+d) , then rationalization of the integral is affected by the substitution (ax+b)/(cx+d)=t^(m) , where m is L.C.M. of fractional powers of (ax+b)/(cx+d) . int(dx)/((x+1)^(2//3)(x-1)^(4//3))=k[(1+x)/(1-x)]^(1//3)+C then

Solving linear inequation in one variable + algorithm (ax+b)/(cx+d)<> =k

Differentiate the following function with respect of x:(ax+b)/(cx+d)

By solving equations 3x + 4y = 23 and 5x + 12y = 39 with the help of cross multiplication method, we obtain (x)/(a) = (y)/(b) = (1)/(c ) , then find (a + 4b)/(5c) .

By solving equations 3x+4y=25 and 4x + 3y=24 with the help of cross - multiplication method, we obtain (x)/(a)=(y)/(b)=(1)/(c). Then, (a+b)/(c) is equal to