[" If "f(x)=2+(x-1)^(2),x in[0,2]," then Rolle's theorem "],[" satisfies at "]

If f(x)=x^(2)-5x+9, x in [1,4], then Rolle's theorem satisfies at

Let f(x) = x(x-1)(x-2),x in [0,2]. Prove that 'f' satisfies the conditions of Rolle's Theorem and there is more than one 'c' in (0,2) such that f'(C ) = 0

If f(x)={{:(x,olexle1),(2-x,1lexle2'):} then Rolle's theorem is not applicable to f(x) because

Verify Rolle's theorem for each of the following functions : Show that f(x) = x (x -5)^(2) satisfies Rolle's theorem on [0, 5] and that the value of c is (5//3)

The point where the function f(x)=x^(2)-4x+10 on [0,4] satisfies the conditions of Rolle's theorem is

If the function f(x)=x^3-6x^(2)+ax+b satisfies Rolle's theorem in the interval [1,3] and f'((2sqrt(3)+1)/(sqrt(3)))=0 , then

If f(x) = x^(3) + bx^(2) + ax satisfies the conditions of Rolle's theorem in [1, 3] with c = 2 + (1)/sqrt(3) then (a, b) is equal to

Let f(x)={(x^(a) , x > 0),(0, x=0):} .Rolle's theorem is applicable to f for x in[0,1] ,if a : (A) -2 (B) -1 (C) 0 (D) (1)/(2)

If f(x) = x^(3) + bx^(2) +ax satisfies the conditions of Rolle's theorem on [1,3] with c = 2+(1)/(sqrt(3)) then (a,b) =0

If the function f(x) = x^(3) - 6x^(2) + ax + b satisfies Rolle's theorem in the interval [1,3] and f'[(2sqrt(3)+1)/sqrt(3)]=0 , then a=