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If f(x)=(a1x+b1)^2+(a2x+b2)^2+...+(an x+...

If `f(x)=(a_1x+b_1)^2+(a_2x+b_2)^2+...+(a_n x+b_n)^2` , then prove that `(a_1b_1+a_2b_2++a_n b_n)^2lt=(a1 2+a2 2++a n2)^(b1 2+b2 2++b n2)dot`

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