[" The function "f:R-{x:alpha+6x-8x^(2)=0,x in R}rarr R" where "R" is the set of real numbers is defined "],[" by "f(x)=(alpha x^(2)+6x-8)/(alpha+6x-8x^(2))," then the correct statement is "]

A function f:RtoR where R is the set of real numbers,is defined by f(x)=(alphax^2+6x-8)/(alpha+6x-8x^2) value of alpha for which f is onto.

If f:R rarr R,f(x)=(alpha x^(2)+6x-8)/(alpha+6x-8x^(2)) is onto then alpha in

R is the set of real numbers,If f:R rarr R is defined by f(x)=sqrt(x) then f is

A function f : R rarr R, where R is the set of real numbers, is defined by : f(x)= (alpha x^2+6x-8)/(alpha+6x-8x^2) . Find the interval of values of alpha for which f is onto. Is the function one-one for alpha = 3 ? Justify your answer.

If f: R->R ,f(x)=(alphax^2+6x-8)/(alpha+6x-8x^2) is onto then alpha in

If f: R->R ,f(x)=(alphax^2+6x-8)/(alpha+6x-8x^2) is onto then alpha in

A function f:IR rarr IR, where IR, is the set of real numbers,is defined by f(x)=(ax^(2)+6x-8)/(a+6x-8x^(2)) Find the interval of values of a for which is onto.Is the functions one-to-one for a=3? Justify your answer.

A function f: IR ->IR , where IR , is the set of real numbers, is defined by f(x) = (ax^2 + 6x - 8)/(a+6x-8x^2) Find the interval of values of a for which is onto. Is the functions one-to-one for a =3 ? Justify your answer.

A function f: IR ->IR , where IR , is the set of real numbers, is defined by f(x) = (ax^2 + 6x - 8)/(a+6x-8x^2) Find the interval of values of a for which is onto. Is the functions one-to-one for a =3 ? Justify your answer.

If R is the set of all real numbers and if f: R -[2] to R is defined by f(x)=(2+x)/(2-x) for x in R-{2} , then the range of is: