" 32."int(cos theta d theta)/((1-sin theta)(2-sin theta))

int (cos theta d theta)/(sin^(2) theta - 5 sin theta)

Evaluate int_(0)^((pi)/(2))(cos theta d theta)/((sin theta +2)(sin theta +3)) .

int(sin theta+cos theta)/(sqrt(1+sin2 theta))d theta

int_(0)^((pi)/(2))(cos theta-sin theta)/((1+cos theta)(1+sin theta))d theta equals -

(2 sin theta*cos theta - cos theta)/(1-sin theta+sin^2 theta-cos^2 theta) = cot theta

int (1 + cos theta) / (theta + sin theta) d theta

int cos 2theta log ((cos theta+sin theta)/(cos theta-sin theta))d theta

int cos2 theta * ln ((cos theta + sin theta) / (cos theta-sin theta)) d theta

int((sin theta-cos theta)d theta)/((sin theta+cos theta)sqrt(sin^(2) theta cos^(2)theta+sin theta cos theta))