sqrt(3)cot20^(@)cot40^(@)cot80^(@)

Find the value: sqrt3 cot20^(@) cot40^(@)cot80^(@)

cot10^(@)cot20^(@)cot60^(@)cot70^(@)cot80^(@)=

sqrt(3)cot20^(@)-4cos20^(@)=

Without using trigonometric tables , prove that : (i) tan20^(@)tan40^(@) tan45^(@)tan50^(@)tan70^(@)=1 (ii) tan1^(@) tan2^(@)tan60^(@)tan88^(@)tan89^(@)=sqrt(3) (iii) cot5^(@)cot10^(@)cot30^(@)cot80^(@)cot85^(@)=sqrt(3) (iv) 4sin10^(@)sin20^(@)sin30^(@)sec70^(@)sec80^(@)=2

Without using trigonometric tables , prove that : (i) tan20^(@)tan40^(@) tan45^(@)tan50^(@)tan70^(@)=1 (ii) tan1^(@) tan2^(@)tan60^(@)tan88^(@)tan89^(@)=sqrt(3) (iii) cot5^(@)cot10^(@)cot30^(@)cot80^(@)cot85^(@)=sqrt(3) (iv) 4sin10^(@)sin20^(@)sin30^(@)sec70^(@)sec80^(@)=2

Find the value of cot10^(@).cot20^(@).cot60^(@).cot70^(@).cot80^(@) .

sqrt3 cot20^(@)-4cos20^(@)=

If (3+cot80^(@)cot 20^(@))/(cot80^(@)+cot20^(@))=tan.(pi)/(k) , then the value of k is (where, (pi)/(k) is an acute angle)

Evaluate : cot 10^(@) .cot20^(@).cot30^(@).cot40^(@) ………cot90^(@) .

Prove that cot12^(@)cot38^(@)cot52^(@)cot78^(@)cot60^(@)=(1)/(sqrt3)