Let omega= e^((ipi)/3) and a, b, c, x,...

Let ` omega= e^((ipi)/3) and a, b, c, x, y, z` be non-zero complex numbers such that `a+b+c = x, a + bomega + comega^2 = y, a + bomega^2 + comega = z`.Then, the value of `(|x|^2+|y|^2|+|y|^2)/(|a|^2+|b|^2+|c|^2)`

Similar Questions

Explore conceptually related problems

Let omega=e^((i pi)/(3)) and a,b,c,x,y,z be non-zero complex numbers such that a+b+c=x,a+b omega+c omega^(2)=y,a+b omega^(2)+c omega=z Then,the value of (|x|^(2)+|y|^(2)|+|y|^(2))/(|a|^(2)+|b|^(2)+|c|^(2))

Let omega =e^(ipi/3) and a,b,c,x,y,z be nonzero complex number such that a+b+c=x, a+bomega+comega^2=y, a+bomega^2+comega=z . Then the value of (|x|^2+|y|^2+|z|^2)/(|a|^2+|b|^2+|c|^2) is

If =a+b,y=aomega+bomega^2 and z=aomega^2+bomega, prove tht xyz=a^3+b^3

If omega be an imaginary cube root of unity, show that (a+bomega+comega^2)/(aomega+bomega^2+c) = omega^2

If omega is a cube root of unity, prove that (a+bomega+comega^2)/(c+aomega+bomega^2)=omega^2

Let ` omega= e^((ipi)/3) and a, b, c, x, y, z` be non-zero complex numbers such that `a+b+c = x, a + bomega + comega^2 = y, a + bomega^2 + comega = z`.Then, the value of `(|x|^2+|y|^2|+|y|^2)/(|a|^2+|b|^2+|c|^2)`

Similar Questions

Recommended Questions