sec theta-1=(sqrt(2)-1)tan theta

IF cos theta ne 0, and sec theta-1=(sqrt2-1) tan theta then theta=

If tan theta =(1)/(sqrt(7)) and theta is an acute angle , then ("cosec"^(2) theta - sec^(2) theta )/( "cosec"^(2) theta + sec^(2) theta =

(1+sec 2 theta)*sqrt(sec^(2) theta-1)= A) 2 sec theta B) sec 2 theta C) 2 tan theta D) tan 2 theta

prove that (tan theta) / (sec theta -1) = (tan theta + sec theta + 1) / (tan theta + sec theta - 1)

Prove: (tan theta)/(sec theta-1)=(tan theta+sec theta+1)/(tan theta+sec theta-1)

prove that (sec theta-tan theta-1)/(sec theta+tan theta-1)=tan theta-sec theta

( tan theta)/( sec theta -1)-(tan theta )/( sec theta + 1)=

If "sec" theta "tan" theta =sqrt(2),"then" theta=

For theta_(1), theta_(2), ...., theta_(n) in (0, pi/2) , if In (sec theta_(1)-tan theta_(1))+ "In" (sec theta_(2)-tan theta_(2))+...+"In" (sec theta_(n)-tan theta_(n))+ "ln" pi=0 , then the value of cos((sec theta_(1)+ tan theta_(1))(sec theta_(2)+tan theta_(2))....(sec theta_(n)+tan theta_(n))) is equal to