if `x=a(costheta+thetasintheta) , y=a(sintheta-thetacostheta)` then `(d^2y)/(dx^2)`

If x=a(costheta+thetasintheta),y=a(sintheta-thetacostheta)," then "(dy)/(dx)=

Find dy/dx of x=a(costheta+thetasintheta) , y=a(sintheta-thetacostheta)

If x=a(costheta+thetasintheta) , y=a(sintheta-thetacostheta) , prove that (d^2x)/(d theta^2)=a(costheta-thetasintheta) , (d^2y)/(d theta^(2))=a(sintheta+thetacostheta) and (d^2y)/(dx^2)=(s e c^3theta)/(a\ theta)

Consider the curve x=a(cos theta+thetasintheta) and y=a(sin theta-thetacostheta) . what is (d^(2)y)/(dx^(2)) equal to ?

Consider the curve x=a(cos theta+thetasintheta) and y=a(sin theta-thetacostheta) . What is (dy)/(dx) equal to ?

If x= a(costheta + sintheta), y= a(sintheta + costheta) , then (d^2y)/(dx^2) at theta = pi/4 .............

Find (dy)/(dx) , if x=a(costheta+thetasintheta) , y=a(sintheta-thetacostheta)

Find y_2 in each of the following cases: x=a(costheta+thetasintheta),y=a(sintheta-thetacostheta) at theta=pi/4

If x=ae^(theta)(sintheta-costheta),y=ae^(theta)(sintheta+costheta)," then "((dy)/(dx))" at "theta=(pi)/(2) is