" 14."4-(2(z-4))/(3)=(1)/(2)(2z+5)

find z . 5-2((z-4)/3) =1/2(2z +3)

The line which passes through the origin and intersect the two lines (x-1)/(2)=(y+3)/(4)=(z-5)/(3) and (x-4)/(2)=(y+3)/(2)=(z-14)/(4) is :

((3)/(7)z-(1)/(2))/(z-(1)/(4))-(3)/(14)=(1)/(7)

Show that the lines : (i) (x -5)/(7) = (y + 2)/(-5) = (z)/(1) " " and (x)/(1) = (y)/(2) = (z)/(3) (ii) (x - 3)/(2) = (y + 1)/(-3) = (z - 2)/(4) and (x + 2)/(2) = (y - 4)/(4) = (z + 5)/(2) are perpendicular to each other .

If z_(1) = 1 - 3i, z_(2) = -4i and z_(3) = 5, show that (z_(1)z_(2)) z_(3) = z_(1) (z_(2)z_(3))

The straight lines (x-3)/(2)=(y+5)/(4)=(z-1)/(-13)and(x+1)/(3)=(y-4)/(5)=(z+2)/(2) are

The point z_(1),z_(2),z_(3),z_(4) in the complex plane are the vertices of a parallogram taken in order, if and only if. (1) z _(1) +z_(4)=z_(2)+z_(3) (2) z_(1)+z_(3) =z_(2) +z_(4) (3) z_(1)+z_(2) =z_(3)+z_(4) (4) z_(1) + z_(3) ne z_(2) +z_(4)

If z_(1) = 1 - 3i, z_(2) = -4i and z_(3) = 5, show that (z_(1) + z_(2)) + z_(3) = z_(1) + (z_(2) + z_(3))

If z_(1)=-3+4i and z_(2)=12-5i, "show that", |(z_(1))/(z_(2))|=(|z_(1)|)/(|z_(2)|)