[(x-3y-7=0],[3x-3y-15=]

Which of the following pairs of linear equations has unique solution, no solution, or infinitely many solution, no solution, or ininitely many solutions. In case there is a unique solution, find it by using cross multiplication method. x-3y-7=0 and 3x-3y-15=0

Solve [2x+3y-7=0],[3x+2y-8=0]

solve for x and y 2x-3y+7=0 3x+4y-5=0

2x+3y-5=0,2x+3y+15=0,x+y-7=0,x+y+7=0 are sides of a parallelogram.Then the centre of the parallelogram is

Prove that the three lines 5x+3y-7=0, 3x-4y=10, and x+2y=0 meet in a point.

Find the solution of 3x-5y+1=0,-7x+3y+15=0

If the lines 5x+3y-15=0 and 3x+5y-15=0 cut both the axes at A,B,C and D then

Given the four lines with the equations x+2y-3=0 , 3x+4y-7=0 , 2x+3y-4=0 , 4x+5y-6=0 , then

Given the four lines with the equations x+2y-3=0 , 3x+4y-7=0 , 2x+3y-4=0 , 4x+5y-6=0 , then