The resultant of two forces `vecP` and `vecQ` acting at O at `vecR` . If any traversal cuts them at A,B and C, respectively, show that `P/(OA)+Q/(OB)=R/(OC)`

The sum of two forces vecP and vecQ is vecR such that |vecR|=|vecP| . The angle theta (in degrees) that the resultant of 2vecP and vecQ will make with vecQ is , _____________.

The sum of two forces vecP and vecQ is vecR such that |vecR|=|vecP| . The angle theta (in degrees) that the resultant of 2vecP and vecQ will make with vecQ is , _____________.

The resultant of two vectors vecP and vecQ is perpendicular to the vector vecP and its magnitude is equal to half of the magnitude of vector vecQ . Then the angle between P and Q is

vecR is the resultant of two vectors vecP and vecQ . When vecQ is reversed , the resultant is vecS . Prove that R^2+S^2=2(P^2+Q^2) .

The resultant of forces vecP and vecQ is vecR. If vecQ is doubles then vecR is doubled. If the direction of vecQ is reversed then vecR is again doubled . Then P^2:Q^2:R^2 is (A) 3:1:1 (B) 2:3:2 (C) 1:2:3 (D) 2:3:1

Two foreces vecP and vecQ are acting at a point . If vecP is reversed, the new resultant becomes between magnitudes of P and Q is given by P = KQ . Find k.

Show that the absolute value of the resultant of two vectors vecP and vecQ cannot be greater than P+Q or less than P-Q.