In the figure shown if friction co-efficient of block 1 and 2 with inclined plane is `mu_1=0.5` and `mu_2=0.4` respectively, then find out the correct statement.

In the figure shown if friction coefficient of block 1kg and 2kg with inclined plane is mu_(1)=0.5 and mu_(2)=0.4 respectively, then

In the figure shown, if friction coefficient of block 1 kg and 2kg with inclined plane is mu_(1) = 0.5 and mu_(2) = 0.4 respectively, then

In the figure shown, if friction coefficient of block 1 kg and 2kg with inclined plane is mu_(1) = 0.5 and mu_(2) = 0.4 respectively, then

Two blocks of masses m_1 = 4 kg and m_2 = 2kg connected by a massless rod slide down on an inclined plane of inclination 37^o as shown in figure. If coefficient of friction of m_1 and m_2 with inclined plane are mu_1 = 0.75 and mu_2 = 0.25 respectively, then tension (T) in the rod is (g = 10 ms^-2 )

Two blocks of masses m, = 4 kg and m, = 2 kg connected by a massless rod slide down on an inclined plane of inclination 37 degree as shown in figure. If coefficient of friction of m_1 and m_2 with inclined plane are mu_1 = 0.75 and mu_2 = 0.25 respectively, then tension (T) in the rod is (g = 10 ms^-2)

In the figure shown, find ._(1)mu_2.

In the figure shown, find ._(1)mu_2.

Two blocks m_(1) = 4 kg and m_(2) = 2 kg connected by a weightless rod slide down a plane having an inclination of 37^(@) . The coefficient of dynamic friction of m_(1) and m_(2) with the inclined plane are mu_(1) = 0 .75 and mu_(2) = 0 . 25 respectively Find the common acceleration of the two blocks and tension in the rod Take is 37^(@) = 0.6 and cos 37^(@) = 0 .8 .

In the arrangement shown in figure coefficient of friction between 5kg block and incline plane is mu=0.5 . Friction force acting on the 5kg block is