Dividing `f(z)` by `z- i`, we obtain the remainder i and dividing it by `z + i`, we get the remainder 1 + i, then remainder upon the division of `f(z)` by `z^2+1` is

Dividing f(z) by z-i, we obtain the remainder 1-i and dividing it by z+i, we get the remainder 1+i. Then, the remainder upon the division of f(z) by z^(2)+1 , is

On dividing a positive integers n by 9, we get 7 as remainder. What will be the remainder if ( 3n-1) is divided by 9 ?

A number divided by 13 leaves a remainder 1 and if the quotient, thus obtained, is divided by 5, we get a remainder of 3. What will be the remainder if the number is divided by 65? 16 (b) 18 (c) 28 (d) 40

When a natural number x is divided by 5, the remainder is 2. When a natural number y is divided by 5, the remainder is 4, The remainder is z when x+y is divided by 5. The value of (2z-5)/(3) is

Find the remainder when the polynomital p(z)=z^(3)-3z+2 is divided by z-2.

On dividing a number by 13, we get 1 as remainder. If the quotient is divided by 5. we get 3 as a remainder. If this number is divided by 65, what will be the remainder ?

| z | -z = 1 + 2i

If the polynomials az^(3)+4z^(2)+3z-4 and z^(3)-4z+a leave the same remainder when divided by z-3, find the value of a.