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" of "y=sec^(-1)((x+1)/(x-1))+cosec^(-1)...

" of "y=sec^(-1)((x+1)/(x-1))+cosec^(-1)((x+1)/(x-1))" find "

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If y=sec^(-1)((x+1)/(x-1))+sin^(-1)((x-1)/(x+1)) , then find (dy)/(dx) .

If y="cosec"^(-1)((x+1)/(x-1))+cos^(-1)((x-1)/(x+1)) , then (dy)/(dx) is equal to -

sec (cosec^(-1) x)=

For the curve defined as y=cosec^(-1)((1+x^2)/(2x))+sec^(-1)((1+x^2)/(1-x^2)) the set of points at which the tangent is parallel to the x axis

Solve sec^(-1) x gt cosec^(-1) x

Solve sec^(-1) x gt cosec^(-1) x

Draw the graph of y=sec^(-1)x+cosec^(-1)x

Draw the graph of y=sec^(-1)x+cosec^(-1)x

Draw the graph of y=sec^(-1)x+cosec^(-1)x

Draw the graph of y=sec^(-1)x+cosec^(-1)x