" 23."((2x+1))/((x^(2)+4x+1)^((3)/(2)))dx

int((2x+1))/((x^(2)+4x+1)^(3//2))dx

int((2x+1))/((x^(2)+4x+1)^(3//2))dx

Evaluate: int((2x+1))/((x^(2)+4x+1)^(3//2))dx

Evaluate: int((2x+1))/((x^(2)+4x+1)^(3//2))dx

Evaluate: int((2x+1))/((x^(2)+4x+1)^(3//2))dx

int((2x+1))/((x^(2)+4x+1)^(3//2))dx= a) (x^(3))/((x^(2)+4x+1)^(1//2))+C b) (x)/((x^(2)+4x+1)^(1//2))+C c) (x^(2))/((x^(2)+4x+1)^(1//2))+C d) (1)/((x^(2)+4x+1)^(1//2))+C

int(2x^(3)+1)/((2x^(4)+4x+1)^(3))dx

int(2x^(3)+1)/((2x^(4)+4x+1)^(3))dx

int((1)/(5+4x^(2))+a^(3x+2))dx

int ((x ^ (-6) -64) / (4 + 2x ^ (-1) + x ^ (-2)) * (x ^ (2)) / (4-4x ^ (-1) + x ^ (-2))-(4x ^ (2) (2x + 1)) / (1-2x)) dx