" 3) "(x+2y^(3))dy=ydx

Solve: (x+2y^(3))dy=ydx

Solution of differential equation (x+2y^(3))dy=ydx is

Solution of differential equation of (x+2y^3)dy = ydx is :

(2x-10y^(3))dy+ydx=0

If the solution curve of the differential equation (2x-10y^(3))dy+ydx =0 , passes through the points (0, 1) and (2, beta) , then beta is a root of the equation :

ydx - (x + 2y ^(2) ) dy = 0

Solve: y^(4)dx+2xy^(3)dy=(ydx-xdy)/(x^(3)y^(3))

Solve: y^(4)dx+2xy^(3)dy=(ydx-xdy)/(x^(3)y^(3))