If the shortest distance between the lines `(x-1)/alpha= (y+1)/-1 =z/1` and `x+y+z+1=0=2x-y+z+3` is `1/sqrt3` then value of `alpha`

Similar Questions

Explore conceptually related problems

The shortest distance between the lines (x-1)/(0)=(y+1)/(-1)=(z)/(1) and x+y+z+1=0, 2x-y+z+3=0 is :

Find the shortest distance between the lines , (x-1)/2=(y-3)/4=(z+2)/1 and 3x-y-2z+4=0=2x+y+z+1 .

Find the shortest distance between the lines,(x-1)/(2)=(y-3)/(4)=(x+2)/(1) and 3x-y-2z+4=0=2x+y+z

The shortest distance between the lines x=y+2 = 6z-6 and x + 1 = 2y = - 12z is

The shortest distance between the lines (x-1)/2= (y-1)/3=(z+2)/6and (x-2)/4=(y+1)/1=(z-3)/7

The shortest distance between the lines 2x+y+z-1=0=3x+y+2z-2 and x=y=z, is

The shortest distance between the lines 2x+y+z-1=0=3x+y+2z-2 and x=y=z , is

The shortest distance between the line 1+x=2y=-12z and x=y+2=6z-6 is

Find the shortest distance between the lines (x+1)/7=(y+1)/(-6) =(z+1)/1 and (x-3)/1=(y-5)/-2=(z-7)/1