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Cosine of the angle of intersection of c...

Cosine of the angle of intersection of curves `y = 3^(x-1) logx and y= x^(x)-1` at (1,0) is

A

1

B

`1/2`

C

0

D

`1/3`

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The correct Answer is:
To find the cosine of the angle of intersection of the curves \( y = 3^{(x-1)} \log x \) and \( y = x^x - 1 \) at the point \( (1, 0) \), we will follow these steps: ### Step 1: Find the derivatives of the curves 1. **For the first curve \( y_1 = 3^{(x-1)} \log x \)**: - We can rewrite \( y_1 \) as \( y_1 = e^{(x-1) \ln 3} \log x \). - To differentiate, we will use the product rule: \[ \frac{dy_1}{dx} = \frac{d}{dx}(e^{(x-1) \ln 3}) \cdot \log x + e^{(x-1) \ln 3} \cdot \frac{d}{dx}(\log x) \] - The derivative of \( e^{(x-1) \ln 3} \) is \( \ln 3 \cdot e^{(x-1) \ln 3} \). - The derivative of \( \log x \) is \( \frac{1}{x} \). - Thus, we have: \[ \frac{dy_1}{dx} = \ln 3 \cdot 3^{(x-1)} \log x + 3^{(x-1)} \cdot \frac{1}{x} \] 2. **For the second curve \( y_2 = x^x - 1 \)**: - We can differentiate \( y_2 \) using the formula for \( x^x \): \[ \frac{dy_2}{dx} = x^x \left( \ln x + 1 \right) \] ### Step 2: Evaluate the derivatives at the point \( (1, 0) \) 1. **Evaluate \( \frac{dy_1}{dx} \) at \( x = 1 \)**: \[ \frac{dy_1}{dx} \bigg|_{x=1} = \ln 3 \cdot 3^{(1-1)} \log 1 + 3^{(1-1)} \cdot \frac{1}{1} = \ln 3 \cdot 1 \cdot 0 + 1 \cdot 1 = 1 \] 2. **Evaluate \( \frac{dy_2}{dx} \) at \( x = 1 \)**: \[ \frac{dy_2}{dx} \bigg|_{x=1} = 1^1 \left( \ln 1 + 1 \right) = 1 \cdot (0 + 1) = 1 \] ### Step 3: Find the angle of intersection - Let \( m_1 = \frac{dy_1}{dx} \bigg|_{x=1} = 1 \) and \( m_2 = \frac{dy_2}{dx} \bigg|_{x=1} = 1 \). - The formula for the tangent of the angle \( \theta \) between two curves is given by: \[ \tan \theta = \left| \frac{m_2 - m_1}{1 + m_1 m_2} \right| \] - Substituting the values: \[ \tan \theta = \left| \frac{1 - 1}{1 + 1 \cdot 1} \right| = \left| \frac{0}{2} \right| = 0 \] - Therefore, \( \theta = \tan^{-1}(0) = 0 \). ### Step 4: Find the cosine of the angle - The cosine of the angle \( \theta \) is: \[ \cos \theta = \cos(0) = 1 \] ### Final Answer The cosine of the angle of intersection of the curves at the point \( (1, 0) \) is \( \boxed{1} \).
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