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The angle of elevation of a stationer...

The angle of elevation of a stationery cloud from a point 2500 m above a lake is `15o` and the angle of depression of its reflection in the lake is `45o` . What is the height of the cloud above the lake level? (Use `tan15o=0. 268` )

Text Solution

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The correct Answer is:
`H=2500sqrt(3)`cm
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The angle of elevation of a stationery cloud from a point 2500 m above a lake is 15o and the angle of depression of its reflection in the lake is 450. What is the height of the cloud above the lake level? (Use tan 15o =0.268)

The angle of elevation of a stationary cloud from a point 2500 m above a lake is 15^(@) and the angle of depression of its reflection in the lake is 45^(@) . The height of the clound above lake level is 2500sqrt(3) metres.

Knowledge Check

  • The angle of elevation of a stationarly cloud from a point 2500 m above a lake is 15^(@) and the angle of depression of its reflection in the lake is 45^(@) . Then find the height of cloud above the lake level.

    A
    `1000sqrt(3)m`
    B
    `1500sqrt(3)m`
    C
    `2500sqrt(3)m`
    D
    `3000sqrt(3)m`

  • The angle of elevation of a stationary cloud from a point 2500 m above a lake is 15^(@) and the angle of depression of its reflection in the lake is 45^(@) . The height of the cloud above the lake level is

    A
    `2500 sqrt(3) m`
    B
    `2500 sqrt(2) m`
    C
    `1500 m`
    D
    `1500 sqrt(3) m`

  • The angle of elevation of a stationary cloud from a point 2500m m above a lake is 15^(@) and the angle of depression of its image in the lake is 45^(@). The height the cloud above the lake level is

    A
    A. 2500 m
    B
    B. `2500 sqrt3 m`
    C
    C.`5000 m `
    D
    D. `500 sqrt3 m`

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